Worked Example: Finding Alumina's Formula

A sample contains 53.96 g aluminium and 48.00 g oxygen. What is the empirical formula?

Step 1: Moles — Al: 53.96 ÷ 26.982 = 2.00 mol; O: 48.00 ÷ 15.999 = 3.00 mol.
Step 2: Divide by smallest — 2.00/2.00 : 3.00/2.00 = 1 : 1.5.
Step 3: Clear the half — ×2 → Al2O3.
Step 4: Check — formula mass = 2(26.982) + 3(15.999) = 101.96 g/mol ✓.